is a town located in Jackson County, Florida
. As of the 2000
census, the town had a total population of 1,919.
Geography\nSneads is located at 30°42'35" North, 84°55'33" West (30.709836, -84.925869)1
According to the United States Census Bureau
, the town has a total area of 12.0 km²
). 11.4 km² (4.4 mi²) of it is land and 0.5 km² (0.2 mi²) of it is water. The total area is 4.54% water.
Demographics\nAs of the census
, there are 1,919 people, 796 households, and 554 families residing in the town. The population density
is 167.6/km² (434.0/mi²). There are 887 housing units at an average density of 77.5/km² (200.6/mi²). The racial makeup of the town is 79.05% White, 16.78% African American
, 0.89% Native American
, 0.10% Asian
, 0.00% Pacific Islander, 1.93% from other races, and 1.25% from two or more races. 3.34% of the population are Hispanic
of any race.
There are 796 households out of which 31.7% have children under the age of 18 living with them, 50.6% are married couples living together, 13.6% have a female householder with no husband present, and 30.4% are non-families. 27.3% of all households are made up of individuals and 12.6% have someone living alone who is 65 years of age or older. The average household size is 2.41 and the average family size is 2.90.
In the town the population is spread out with 25.5% under the age of 18, 9.0% from 18 to 24, 26.5% from 25 to 44, 24.5% from 45 to 64, and 14.5% who are 65 years of age or older. The median age is 37 years. For every 100 females there are 95.8 males. For every 100 females age 18 and over, there are 90.9 males.
The median income for a household in the town is $30,690, and the median income for a family is $37,162. Males have a median income of $25,917 versus $23,674 for females. The per capita income for the town is $15,113. 17.2% of the population and 11.2% of families are below the poverty line. Out of the total people living in poverty, 27.1% are under the age of 18 and 11.0% are 65 or older.