Rome, Jefferson County, WisconsinRome
is a town located in Jefferson County, Wisconsin
. As of the 2000
census, the town had a total population of 574.
Geography\nRome is located at 42°58'50" North, 88°37'54" West (42.980687, -88.631634)1
According to the United States Census Bureau
, the town has a total area of 10.7 km²
). 10.2 km² (3.9 mi²) of it is land and 0.5 km² (0.2 mi²) of it is water. The total area is 5.07% water.
Demographics\nAs of the census
, there are 574 people, 220 households, and 168 families residing in the town. The population density
is 56.2/km² (145.7/mi²). There are 236 housing units at an average density of 23.1/km² (59.9/mi²). The racial makeup of the town is 99.30% White, 0.17% African American
, 0.35% Native American
, 0.00% Asian
, 0.00% Pacific Islander, 0.00% from other races, and 0.17% from two or more races. 0.52% of the population are Hispanic
of any race.
There are 220 households out of which 29.1% have children under the age of 18 living with them, 66.8% are married couples living together, 5.9% have a female householder with no husband present, and 23.6% are non-families. 18.6% of all households are made up of individuals and 5.5% have someone living alone who is 65 years of age or older. The average household size is 2.61 and the average family size is 2.98.
In the town the population is spread out with 23.7% under the age of 18, 7.3% from 18 to 24, 30.5% from 25 to 44, 25.8% from 45 to 64, and 12.7% who are 65 years of age or older. The median age is 39 years. For every 100 females there are 100.7 males. For every 100 females age 18 and over, there are 102.8 males.
The median income for a household in the town is $55,357, and the median income for a family is $60,875. Males have a median income of $36,938 versus $24,063 for females. The per capita income for the town is $20,622. 5.3% of the population and 2.3% of families are below the poverty line. Out of the total people living in poverty, 11.5% are under the age of 18 and 0.0% are 65 or older.