is a town located in Jackson County, Florida
. As of the 2000
census, the town had a total population of 466.
Geography\nAlford is located at 30°41'41" North, 85°23'35" West (30.694794, -85.393119)1
According to the United States Census Bureau
, the town has a total area of 3.4 km²
). 3.3 km² (1.3 mi²) of it is land and 0.1 km² (0.04 mi²) of it is water. The total area is 1.53% water.
Demographics\nAs of the census
, there are 466 people, 196 households, and 133 families residing in the town. The population density
is 140.6/km² (362.9/mi²). There are 235 housing units at an average density of 70.9/km² (183.0/mi²). The racial makeup of the town is 96.35% White, 1.50% African American
, 0.86% Native American
, 0.00% Asian
, 0.00% Pacific Islander, 0.21% from other races, and 1.07% from two or more races. 2.36% of the population are Hispanic
of any race.
There are 196 households out of which 30.1% have children under the age of 18 living with them, 48.0% are married couples living together, 14.3% have a female householder with no husband present, and 32.1% are non-families. 29.6% of all households are made up of individuals and 15.8% have someone living alone who is 65 years of age or older. The average household size is 2.38 and the average family size is 2.93.
In the town the population is spread out with 27.7% under the age of 18, 5.6% from 18 to 24, 27.0% from 25 to 44, 23.0% from 45 to 64, and 16.7% who are 65 years of age or older. The median age is 37 years. For every 100 females there are 82.0 males. For every 100 females age 18 and over, there are 82.2 males.
The median income for a household in the town is $19,250, and the median income for a family is $24,375. Males have a median income of $28,333 versus $16,250 for females. The per capita income for the town is $14,689. 36.9% of the population and 27.9% of families are below the poverty line. Out of the total people living in poverty, 52.4% are under the age of 18 and 15.5% are 65 or older.